A capacitor of capacitance 100μF is charged by connecting it to a battery of EMF 12V and internal resistance 2Ω . The time taken before 99 % of the maximum charge is stored on the capacitor-

Question

A capacitor of capacitance 100μF is charged by connecting it to a battery of EMF 12V and internal resistance 2Ω . The time taken before 99 % of the maximum charge is stored on the capacitor- (A) 0.92ms (B) 0.4ms (C) 0.8ms (D) 0.1ms

Tardigrade Admin · Accepted Answer

During charging of capacitor, charge at any instant is

q = q_{0} (1 - e^{t / RC})

0.99 q_{0} = q_{0} (1 - e^{- t / RC})

0.99 = (1 - e^{- t / RC})

0.01 = e^{- t / RC}

e^{t / RC} = 100

t = RCl n (100)

t (2) (100 \times 1 0^{- 6}) (2 \times 2.303)

t = 0.92 m s

Q. A capacitor of capacitance $100 μ F$ is charged by connecting it to a battery of EMF $12 V$ and internal resistance $2Ω$ . The time taken before $99%$ of the maximum charge is stored on the capacitor-

$0.92 m s$

$0.4 m s$

$0.8 m s$

$0.1 m s$

During charging of capacitor, charge at any instant is
$q = q_{0} (1 - e^{t / RC})$
$0.99 q_{0} = q_{0} (1 - e^{- t / RC})$
$0.99 = (1 - e^{- t / RC})$
$0.01 = e^{- t / RC}$
$e^{t / RC} = 100$
$t = RCl n (100)$
$t (2) (100 \times 1 0^{- 6}) (2 \times 2.303)$
$t = 0.92 m s$

Q. A capacitor of capacitance 100μF is charged by connecting it to a battery of EMF 12V and internal resistance 2Ω . The time taken before 99% of the maximum charge is stored on the capacitor-

0.92ms

0.4ms

0.8ms

0.1ms