A bus strats to move with an acceleration of 1 m / s 2. A boy who is 48 m behind the bus starts running at 10 m / s. The minimum time (in s) at which the boy can catch the bus is

Question

A bus strats to move with an acceleration of 1 m / s 2. A boy who is 48 m behind the bus starts running at 10 m / s. The minimum time (in s) at which the boy can catch the bus is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let t be the time in which the boy catches the bus. ∴ 48+(1/2) × 1 × t2=10 t ⇒ t=8 s or 12 s. Minimum time, t=8 s

Q. A bus strats to move with an acceleration of $1 m / s^{2}$ . A boy who is $48 m$ behind the bus starts running at $10 m / s$ . The minimum time (in $s$ ) at which the boy can catch the bus is

Let $t$ be the time in which the boy catches the bus.
$∴ 48 + \frac{1}{2} \times 1 \times t^{2} = 10 t$
$\Rightarrow t = 8 s$
or $12 s$ .
Minimum time, $t = 8 s$

Q. A bus strats to move with an acceleration of 1m/s2. A boy who is 48m behind the bus starts running at 10m/s. The minimum time (in s) at which the boy can catch the bus is

Let t be the time in which the boy catches the bus. ∴48+21​×1×t2=10t ⇒t=8s or 12s. Minimum time, t=8s

Q. A bus strats to move with an acceleration of $1 m / s^{2}$ . A boy who is $48 m$ behind the bus starts running at $10 m / s$ . The minimum time (in $s$ ) at which the boy can catch the bus is

Let $t$ be the time in which the boy catches the bus.
$∴ 48 + \frac{1}{2} \times 1 \times t^{2} = 10 t$
$\Rightarrow t = 8 s$
or $12 s$ .
Minimum time, $t = 8 s$