A bullet of mass 10 g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joule overcoming the resistance of air will be

Question

A bullet of mass 10 g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joule overcoming the resistance of air will be (A) 375 (B) 3750 (C) 5000 (D) 500

Tardigrade Admin · Accepted Answer

Work done = change in kinetic energy of the body W=(1/2) × 0.01[(1000)2-(500)2]=3750 joule.

Q. A bullet of mass $10 g$ leaves a rifle at an initial velocity of $1000 m / s$ and strikes the earth at the same level with a velocity of $500 m / s$ . The work done in joule overcoming the resistance of air will be

375

3750

5000

500

Work done = change in kinetic energy of the body
$W = \frac{1}{2} \times 0.01 [(1000)^{2} - (500)^{2}] = 3750$ joule.

Q. A bullet of mass 10g leaves a rifle at an initial velocity of 1000m/s and strikes the earth at the same level with a velocity of 500m/s. The work done in joule overcoming the resistance of air will be

375

3750

5000

500

Work done = change in kinetic energy of the body W=21​×0.01[(1000)2−(500)2]=3750 joule.

Q. A bullet of mass $10 g$ leaves a rifle at an initial velocity of $1000 m / s$ and strikes the earth at the same level with a velocity of $500 m / s$ . The work done in joule overcoming the resistance of air will be

Work done = change in kinetic energy of the body
$W = \frac{1}{2} \times 0.01 [(1000)^{2} - (500)^{2}] = 3750$ joule.