A bubble in glass slab (μ = 1.5) when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is

Question

A bubble in glass slab (μ = 1.5) when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is (A) 3.75 cm (B) 3 cm (C) 10.5 cm (D) 2.5 cm

Tardigrade Admin · Accepted Answer

Total apparent depth, y=y1 +y2 = 5+2 =7 cm If.v is real depth = thickness of slab, then as μ = (real depth/apparent depth) = (x/y) or x= μ y = 1.5 × 7 = 10.5 cm

Q. A bubble in glass slab $(μ = 1.5)$ when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is

3.75 cm

3 cm

10.5 cm

2.5 cm

Total apparent depth,
$y = y_{1} + y_{2} = 5 + 2 = 7 c m$
If.v is real depth = thickness of slab, then as
$μ = \frac{re a l d e pt h}{a pp a re n t d e pt h} = \frac{x}{y}$
$or x = μ y = 1.5 \times 7 = 10.5 c m$

Q. A bubble in glass slab (μ=1.5) when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is