A boy is standing on a weighing machine inside a lift. When the lift goes upwards with acceleration g/4, the machine shows the reading 50 kg. wt. When the lift goes downward with acceleration g/4, the reading of the machine in kg. wt. would be

Question

A boy is standing on a weighing machine inside a lift. When the lift goes upwards with acceleration g/4, the machine shows the reading 50 kg. wt. When the lift goes downward with acceleration g/4, the reading of the machine in kg. wt. would be (A) 50 (B) 30 (C) 45.5 (D) 62.5

Tardigrade Admin · Accepted Answer

Reading of the weighing balance W1=m(1+(a/g)) kgwt. when it is upwards Given: a=(g/4) ; ω1=50 kgw t ⇒ m=(1+(1/4))=50 kgwt or (5/4) M=50 kgw t Reading of the weighing balance when lift is accelerating downwards is ω2=M(1-(a/g))=(3/4) m kgwt =30 kgw t

Q. A boy is standing on a weighing machine inside a lift. When the lift goes upwards with acceleration $g /4$ , the machine shows the reading $50 k g$ . wt. When the lift goes downward with acceleration $g /4$ , the reading of the machine in kg. wt. would be

$50$

$30$

$45.5$

$62.5$

$14$

Q. A boy is standing on a weighing machine inside a lift. When the lift goes upwards with acceleration g/4, the machine shows the reading 50kg. wt. When the lift goes downward with acceleration g/4, the reading of the machine in kg. wt. would be

50

30

45.5

62.5

14