A bomb is dropped from an aeroplane flying horizontally with a velocity 469 m s- 1 at an altitude of 980 m . The bomb will hit the ground after a time (use g=9.8 m s- 2 )

Question

A bomb is dropped from an aeroplane flying horizontally with a velocity 469 m s- 1 at an altitude of 980 m . The bomb will hit the ground after a time (use g=9.8 m s- 2 ) (A) 2s (B) √2s (C) 5√2s (D) 10√2s

Tardigrade Admin · Accepted Answer

t=√( text2 textith/g)=√(2 ( text980)/ text9.8)= text10√2ms- 1

Q. A bomb is dropped from an aeroplane flying horizontally with a velocity $469 m s^{- 1}$ at an altitude of $980 m$ . The bomb will hit the ground after a time (use $g = 9.8 m s^{- 2}$ )

$2 s$

$2 s$

$52 s$

$102 s$

$t = \frac{2 h}{g} = \frac{2 ( 980 )}{9.8} = 102 m s^{- 1}$

Q. A bomb is dropped from an aeroplane flying horizontally with a velocity 469ms−1 at an altitude of 980m . The bomb will hit the ground after a time (use g=9.8ms−2 )

2s

2​s

52​s

102​s

t=g2h​​=9.82(980)​​=102​ms−1

Q. A bomb is dropped from an aeroplane flying horizontally with a velocity $469 m s^{- 1}$ at an altitude of $980 m$ . The bomb will hit the ground after a time (use $g = 9.8 m s^{- 2}$ )

$2 s$

$2 s$

$52 s$

$102 s$

$t = \frac{2 h}{g} = \frac{2 ( 980 )}{9.8} = 102 m s^{- 1}$