A body of mass m is performing a UCM in a circle of radius r with speed v. The work done by the centripetal force in moving it through ((2/3))rd of the circular path is

Question

A body of mass m is performing a UCM in a circle of radius r with speed v. The work done by the centripetal force in moving it through ((2/3))rd of the circular path is (A) zero (B) mv2π r (C) (2π mv2r/3) (D) (2mv2π/3)

Tardigrade Admin · Accepted Answer

When a body perform uniform circular motion, then centripetal force acts always in perpendicular direction to its velocity, hence work done by centripetal force is always zero. Hence, work done by centripetal force is zero, when it through ((2/3)) rd of the circular path.

Q. A body of mass $m$ is performing a $U CM$ in a circle of radius $r$ with speed $v$ . The work done by the centripetal force in moving it through $(\frac{2}{3}) r d$ of the circular path is

zero

$m v^{2} π r$

$\frac{2 πm v ^{2} r}{3}$

$\frac{2 m v ^{2} π}{3}$

When a body perform uniform circular motion, then centripetal force acts always in perpendicular direction to its velocity, hence work done by centripetal force is always zero. Hence, work done by centripetal force is zero, when it through $(\frac{2}{3})$ rd of the circular path.

Q. A body of mass m is performing a UCM in a circle of radius r with speed v. The work done by the centripetal force in moving it through (32​)rd of the circular path is

zero

mv2πr

32πmv2r​

32mv2π​

When a body perform uniform circular motion, then centripetal force acts always in perpendicular direction to its velocity, hence work done by centripetal force is always zero. Hence, work done by centripetal force is zero, when it through (32​) rd of the circular path.

Q. A body of mass $m$ is performing a $U CM$ in a circle of radius $r$ with speed $v$ . The work done by the centripetal force in moving it through $(\frac{2}{3}) r d$ of the circular path is

$m v^{2} π r$

$\frac{2 πm v ^{2} r}{3}$

$\frac{2 m v ^{2} π}{3}$

When a body perform uniform circular motion, then centripetal force acts always in perpendicular direction to its velocity, hence work done by centripetal force is always zero. Hence, work done by centripetal force is zero, when it through $(\frac{2}{3})$ rd of the circular path.