A body of mass 5 kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is

Question

A body of mass 5 kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/711e96e58ce27b764226e50ee9b06496-.png" /> (A) 0 kg m s -1 (B) 100 kg m s -1 (C) 140 kg m s -1 (D) 200 kg m s -1

Tardigrade Admin · Accepted Answer

Change in momentum = Area under F-t graph = area of trapezium O A B C = (1/2)(10+4) × 20=140 kg m s -1

Q. A body of mass $5 k g$ is acted on by a force $F$ which varies with time $t$ as shown in the given figure. Then the momentum gained by the body at the end of $10$ seconds is

$0 k g m s^{- 1}$

$100 k g m s^{- 1}$

$140 k g m s^{- 1}$

$200 k g m s^{- 1}$

Change in momentum = Area under $F - t$ graph
= area of trapezium $O A BC$
$= \frac{1}{2} (10 + 4) \times 20 = 140 k g m s^{- 1}$

Q. A body of mass 5kg is acted on by a force F which varies with time t as shown in the given figure. Then the momentum gained by the body at the end of 10 seconds is

0kgms−1

100kgms−1

140kgms−1

200kgms−1