A body of mass 45 kg. is moving with a constant velocity of 10 m / s. A constant force acts on the body for four second, and the speed of the body becomes 2 m / s in opposite direction, calculate the magnitude of acceleration produced in m / sec 2.

Question

A body of mass 45 kg. is moving with a constant velocity of 10 m / s. A constant force acts on the body for four second, and the speed of the body becomes 2 m / s in opposite direction, calculate the magnitude of acceleration produced in m / sec 2. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/feec32197d90ed0328c836498c30a6c3-.png" /> m =45 kg F = ma ∴ a=(F/m) from v=4+a t -2=10+a × 4 4 a =-12 ∴ a =-3 m / s 2 ∴ F=m a=45 ×-3=-135 N

Q. A body of mass $45 k g$ . is moving with a constant velocity of $10 m / s$ . A constant force acts on the body for four second, and the speed of the body becomes $2 m / s$ in opposite direction, calculate the magnitude of acceleration produced in $m / sec^{2}$ .

$m = 45 k g$
$F = ma$
$∴ a = \frac{F}{m}$
from $v = 4 + a t$
$- 2 = 10 + a \times 4$
$4 a = - 12 ∴ a = - 3 m / s^{2}$
$∴ F = ma = 45 \times - 3 = - 135 N$

Q. A body of mass 45kg. is moving with a constant velocity of 10m/s. A constant force acts on the body for four second, and the speed of the body becomes 2m/s in opposite direction, calculate the magnitude of acceleration produced in m/sec2.

m=45kg F=ma ∴a=mF​ from v=4+at −2=10+a×4 4a=−12∴a=−3m/s2 ∴F=ma=45×−3=−135N

Q. A body of mass $45 k g$ . is moving with a constant velocity of $10 m / s$ . A constant force acts on the body for four second, and the speed of the body becomes $2 m / s$ in opposite direction, calculate the magnitude of acceleration produced in $m / sec^{2}$ .

$m = 45 k g$
$F = ma$
$∴ a = \frac{F}{m}$
from $v = 4 + a t$
$- 2 = 10 + a \times 4$
$4 a = - 12 ∴ a = - 3 m / s^{2}$
$∴ F = ma = 45 \times - 3 = - 135 N$