A body of mass 40 kg resting on rough horizontal surface is subjected to a force P which is just enough to start the motion of the body. If μs=5, μx=0.4, g=10 m / s 2 and the force P is continuously applied on the body, then the acceleration of the body is

Question

A body of mass 40 kg resting on rough horizontal surface is subjected to a force P which is just enough to start the motion of the body. If μs=5, μx=0.4, g=10 m / s 2 and the force P is continuously applied on the body, then the acceleration of the body is (A) zero (B) 1 m/s2 (C) 2 m/s2 (D) 2 .4 m/s2

Tardigrade Admin · Accepted Answer

Force P=fm=μ0 m g( when body is rest ) When the body starts moving with acceleration a then P-Fk =m a μ0 m g-μk m g =m a a =(μ0-μk) g =(0.5-0.4) 10 =0.1 × 10 m / s 2=1 m / s 2

Q. A body of mass $40 k g$ resting on rough horizontal surface is subjected to a force $P$ which is just enough to start the motion of the body. If $μ_{s} = 5, μ_{x} = 0.4, g = 10 m / s^{2}$ and the force $P$ is continuously applied on the body, then the acceleration of the body is

zero

$1 m / s^{2}$

$2 m / s^{2}$

$2.4 m / s^{2}$

Force $P = f_{m} = μ_{0} m g ($ when body is rest $)$
When the body starts moving with acceleration a then
$P - F_{k} = ma$
$μ_{0} m g - μ_{k} m g = ma$
$a = (μ_{0} - μ_{k}) g$
$= (0.5 - 0.4) 10$
$= 0.1 \times 10 m / s^{2} = 1 m / s^{2}$

Q. A body of mass 40kg resting on rough horizontal surface is subjected to a force P which is just enough to start the motion of the body. If μs​=5,μx​=0.4,g=10m/s2 and the force P is continuously applied on the body, then the acceleration of the body is

zero

1m/s2

2m/s2

2.4m/s2

Force P=fm​=μ0​mg( when body is rest ) When the body starts moving with acceleration a then P−Fk​=ma μ0​mg−μk​mg=ma a=(μ0​−μk​)g =(0.5−0.4)10 =0.1×10m/s2=1m/s2

Q. A body of mass $40 k g$ resting on rough horizontal surface is subjected to a force $P$ which is just enough to start the motion of the body. If $μ_{s} = 5, μ_{x} = 0.4, g = 10 m / s^{2}$ and the force $P$ is continuously applied on the body, then the acceleration of the body is

$1 m / s^{2}$

$2 m / s^{2}$

$2.4 m / s^{2}$

Force $P = f_{m} = μ_{0} m g ($ when body is rest $)$
When the body starts moving with acceleration a then
$P - F_{k} = ma$
$μ_{0} m g - μ_{k} m g = ma$
$a = (μ_{0} - μ_{k}) g$
$= (0.5 - 0.4) 10$
$= 0.1 \times 10 m / s^{2} = 1 m / s^{2}$