Question

A body of mass 10 kg initially at rest acquires velocity $10m{s}^{-1}$. What is the work done

• A. -500 J
• B. 500 J
• C. 50 J
• D. -50 J

Answer 1

Answer: (B)

By work-energy theorem
$W=\Delta K=\frac{1}{2}\times 10\times (10{)}^2-0$
=500 J