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Question
Physics
A body moving with uniform acceleration describes 40 m in the first 5 s and 70 m in the next 5 s . Its initial velocity will be
Q. A body moving with uniform acceleration describes
40
m
in the first
5
s
and
70
m
in the next
5
s
. Its initial velocity will be
3358
197
NTA Abhyas
NTA Abhyas 2020
Motion in a Straight Line
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A
4
m
s
−
1
11%
B
2.5
m
s
−
1
18%
C
5
m
s
−
1
43%
D
11
m
s
−
1
29%
Solution:
s
1
=
40
m
,
s
2
=
70
m
Δ
t
1
=
5
s
,
Δ
t
2
=
5
s
40
=
u
(
Δ
t
1
)
+
2
1
a
(
Δ
t
1
)
2
=
5
u
+
2
1
a
×
25
⇒
2
u
+
5
a
=
16
110
=
u
(
Δ
t
1
+
Δ
t
2
)
+
2
1
a
(
Δ
t
1
+
Δ
t
2
)
2
110
=
10
u
+
2
1
a
×
100
⇒
u
+
5
a
=
11
u
=
5
m
s
−
1