Q.
A body is thrown up in a lift with a velocity 5ms−1 relative to the lift and the time of flight is found to be 0.8s . The acceleration with which the lift is moving up is (g=10ms−2)
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NTA AbhyasNTA Abhyas 2020Motion in a Straight Line
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Solution:
Acceleration of body w. r. t. lift =−(g+a) ∴ Time of flight of body, t=g+a2u ⇒a=t2u−gt=0.8(2×5)−(10×0.8)=2.5ms−2