Q.
A body is projected vertically upward from the surface of the earth with a velocity equal to half its escape velocity. If R is radius of the earth, then the maximum height attained by the body is (R/n). Find n.
Let the body be projected from the surface of the earth with velocity v and reaches maximum height h.
According to law of conservation of mechanical energy, we get 21mv2−RGMm=0−(R+h)GMm
or 21v2−RGM=−(R+h)GM
As per question, V=2Ve=21R2GM [∵ve=R2GM] ⇒21(21RGM)−RGM=−(R+h)GM 4RGM−RGM=−R+hGM −4R3=−(R+h)1 3(R+h)=4R
or 3R+3h=4R 3h=R
or h=3R