A body is moving with velocity 30 ms towards east After 10 s its velocity becomes 40 ms towards north. The average acceleration of the body is

Question

A body is moving with velocity 30 ms towards east After 10 s its velocity becomes 40 ms towards north. The average acceleration of the body is (A) 7 ms-1 (B) √7 ms-1 (C) 5 ms-1 (D) 1 ms-2

Tardigrade Admin · Accepted Answer

Average acceleration vec A text avg =( vec v f - vec v i / t )=(40 hat j -30 hat i /10) vec A text avg =(√402+302/10)=5 m / sec 2

Q. A body is moving with velocity $30 m s$ towards east After 10 s its velocity becomes $40 m s$ towards north. The average acceleration of the body is

$7 m s^{- 1}$

$7 m s^{- 1}$

$5 m s^{- 1}$

$1 m s^{- 2}$

Average acceleration
$A_{avg} = \frac{v _{f} - v _{i}}{t} = \frac{40 j ^ - 30 i ^}{10}$
$A_{avg} = \frac{4 0 ^{2} + 3 0 ^{2}}{10} = 5 m / se c^{2}$

Q. A body is moving with velocity 30ms towards east After 10 s its velocity becomes 40ms towards north. The average acceleration of the body is

7ms−1

7​ms−1

5ms−1

1ms−2

Average acceleration Aavg ​=tvf​−vi​​=1040j^​−30i^​ Aavg ​=10402+302​​=5m/sec2

Q. A body is moving with velocity $30 m s$ towards east After 10 s its velocity becomes $40 m s$ towards north. The average acceleration of the body is

$7 m s^{- 1}$

$7 m s^{- 1}$

$5 m s^{- 1}$

$1 m s^{- 2}$

Average acceleration
$A_{avg} = \frac{v _{f} - v _{i}}{t} = \frac{40 j ^ - 30 i ^}{10}$
$A_{avg} = \frac{4 0 ^{2} + 3 0 ^{2}}{10} = 5 m / se c^{2}$