Q.
A body is moving with an initial velocity of 102m⋅s−1 in the north-east direction. If it is subjected to an acceleration of 2m⋅s−2 directed towards the south, the velocity of the body after 5s is_____
The given situation is shown in the following figure
Initial velocity of body, u=102cos45∘i^+102cos45∘j^ =10i^+10j^=10(i^+j^)
Acceleration applied on body in south direction, aS=2(−j^)=−2j^ ∴ Velocity of body after 5s is given as v=u+aSt=10(i^+j^)+(−2j^)×5 =10i^+10j^−10j^=10i^
Hence, body will move towards east with the velocity 10ms−1.