A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:

Question

A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is: (A) 1 (B) 2 (C) (1/√2) (D) √2

Tardigrade Admin · Accepted Answer

V text orbit =√( GM / R ) V text escape =√(2 GM / R ) ( V text orbit / V text escape )=(1/√2)

Q. A body is moving in a low circular orbit about a planet of mass $M$ and radius $R$ . The radius of the orbit can be taken to be $R$ itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:

$1$

$2$

$\frac{1}{2}$

$2$

$V_{orbit} = \frac{GM}{R}$
$V_{escape} = \frac{2 GM}{R}$
$\frac{V _{orbit}}{V _{escape}} = \frac{1}{2}$

Q. A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:

1

2

2​1​

2​

Vorbit ​=RGM​​ Vescape ​=R2GM​​ Vescape ​Vorbit ​​=2​1​

Q. A body is moving in a low circular orbit about a planet of mass $M$ and radius $R$ . The radius of the orbit can be taken to be $R$ itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:

$1$

$2$

$\frac{1}{2}$

$2$

$V_{orbit} = \frac{GM}{R}$
$V_{escape} = \frac{2 GM}{R}$
$\frac{V _{orbit}}{V _{escape}} = \frac{1}{2}$