A block of mass √2 kg is released from the top of an inclined smooth surface as shown in figure. If spring constant of spring is 100 N / m and block comes to rest after compressing the spring by 1 m, then the distance travelled by block before it comes to rest is

Question

A block of mass √2 kg is released from the top of an inclined smooth surface as shown in figure. If spring constant of spring is 100 N / m and block comes to rest after compressing the spring by 1 m, then the distance travelled by block before it comes to rest is (A) 1 m (B) 1.25 m (C) 2.5 m (D) 5 m

Tardigrade Admin · Accepted Answer

Ui+ki=Uf+kf (m g h sin 45°)+0=(1/2) k(1)2+0 by solving h=5 m

Q. A block of mass $2 k g$ is released from the top of an inclined smooth surface as shown in figure. If spring constant of spring is $100 N / m$ and block comes to rest after compressing the spring by $1 m$ , then the distance travelled by block before it comes to rest is

1 m

1.25 m

2.5 m

5 m

$U_{i} + k_{i} = U_{f} + k_{f}$
$(m g h sin 4 5^{\circ}) + 0 = \frac{1}{2} k (1)^{2} + 0$
by solving $h = 5 m$

Q. A block of mass 2​kg is released from the top of an inclined smooth surface as shown in figure. If spring constant of spring is 100N/m and block comes to rest after compressing the spring by 1m, then the distance travelled by block before it comes to rest is

1 m

1.25 m

2.5 m

5 m

Ui​+ki​=Uf​+kf​ (mghsin45∘)+0=21​k(1)2+0 by solving h=5m

Q. A block of mass $2 k g$ is released from the top of an inclined smooth surface as shown in figure. If spring constant of spring is $100 N / m$ and block comes to rest after compressing the spring by $1 m$ , then the distance travelled by block before it comes to rest is

$U_{i} + k_{i} = U_{f} + k_{f}$
$(m g h sin 4 5^{\circ}) + 0 = \frac{1}{2} k (1)^{2} + 0$
by solving $h = 5 m$