A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 30° by a force of 10 N parallel to the inclined surface as shown in the figure. The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline the work done by applied force is

Question

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 30° by a force of 10 N parallel to the inclined surface as shown in the figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/eb9ba1ec54e3ab5f3edf2c2ec15e0b8d-.jpeg" /> The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline the work done by applied force is (A) 10 J (B) 50 J (C) 100 J (D) 150 J

Tardigrade Admin · Accepted Answer

Work done by applied force is W= Fd= 10 N × 10 m= 100 J

$10 J$

$50 J$

$100 J$

$150 J$

Work done by applied force is
$W = F d = 10 N \times 10 m = 100 J$

10J

50J

100J

150J

Work done by applied force is W=Fd=10N×10m=100J

$10 J$

$50 J$

$100 J$

$150 J$

Work done by applied force is
$W = F d = 10 N \times 10 m = 100 J$