Question

A bivalent metal has the equivalent weight of $12$. The molecular weight of its oxide will be

• A. 36
• B. 24
• C. 40
• D. 32

Answer 1

Answer: (C)

Atomic wt. of metal $=2\times 12$

$=24$

$\therefore$ Mol. wt. of its oxide $=24+16$

$=40$