Here, v=∣t−2∣ms−1 v=t−2, when t>2s v=2−t, when t<2s ∴a=dtdv=1ms−2 when t>2s a=−1ms−2 when t<2s
In the direction of motion from A to C, bee decelerates but for C to B, bee accelerates.
Let AC=s1,BC=s2 uA=2ms−1,t=0 200100,(m)300mrel=+=uC=0at ∴s1=(2uA+uC)t1 s2=(2uC+uB)t2 ∴s=s1+s2=(22+0)2+(20+2)2=4m