A beam of light propagating in medium A with index of refraction μA passes across an interface into medium B with index of refraction μB. The angle of incidence is greater than the angle of refraction, vA and vB denote the speeds of light in A and B respectively. Then which of the following is true?

Question

A beam of light propagating in medium A with index of refraction μA passes across an interface into medium B with index of refraction μB. The angle of incidence is greater than the angle of refraction, vA and vB denote the speeds of light in A and B respectively. Then which of the following is true? (A) vA > vB and μA > μB (B) vA > vB and μA < μB (C) vA < vB and μA > μB (D) vA < vB and μA < μB

Tardigrade Admin · Accepted Answer

Given that i>r. ⇒ μB > μA ⇒ (v/vB) >(v/vA) or vB < vA

$v_{A} > v_{B}$ and $μ_{A} > μ_{B}$

$v_{A} > v_{B}$ and $μ_{A} < μ_{B}$

$v_{A} < v_{B}$ and $μ_{A} > μ_{B}$

$v_{A} < v_{B}$ and $μ_{A} < μ_{B}$

Given that $i > r$ .
$\Rightarrow μ_{B} > μ_{A}$
$\Rightarrow \frac{v}{v _{B}} > \frac{v}{v _{A}}$
or $v_{B} < v_{A}$

vA​>vB​ and μA​>μB​

vA​>vB​ and μA​<μB​

vA​<vB​ and μA​>μB​

vA​<vB​ and μA​<μB​

Given that i>r. ⇒μB​>μA​ ⇒vB​v​>vA​v​ or vB​<vA​

$v_{A} > v_{B}$ and $μ_{A} > μ_{B}$

$v_{A} > v_{B}$ and $μ_{A} < μ_{B}$

$v_{A} < v_{B}$ and $μ_{A} > μ_{B}$

$v_{A} < v_{B}$ and $μ_{A} < μ_{B}$

Given that $i > r$ .
$\Rightarrow μ_{B} > μ_{A}$
$\Rightarrow \frac{v}{v _{B}} > \frac{v}{v _{A}}$
or $v_{B} < v_{A}$