A battery of 6 V and internal resistance 2 Ω is connected to a silver voltameter. If the current of 1.5 A flows through the circuit, the resistance of the voltameter is

Question

A battery of 6 V and internal resistance 2 Ω is connected to a silver voltameter. If the current of 1.5 A flows through the circuit, the resistance of the voltameter is (A) 4 Ω (B) 2 Ω (C) 6 Ω (D) 1 Ω

Tardigrade Admin · Accepted Answer

Given, E=-6 V, r=2 Ω and i=1.5 A We know that, current across a circuit, i =(E/r +R) ⇒ 1.5 =(6/2+R) ⇒ 2+R =(6/1.5) or, R =4-2=2 Ω

Q. A battery of $6 V$ and internal resistance $2Ω$ is connected to a silver voltameter. If the current of $1.5 A$ flows through the circuit, the resistance of the voltameter is

$4 Ω$

$2 Ω$

$6 Ω$

$1 Ω$

$5 Ω$

Given,
$E = - 6 V, r = 2Ω$ and $i = 1.5 A$
We know that, current across a circuit,
$i = \frac{E}{r + R}$
$\Rightarrow 1.5 = \frac{6}{2 + R}$
$\Rightarrow 2 + R = \frac{6}{1.5}$
or, $R = 4 - 2 = 2Ω$

Q. A battery of 6V and internal resistance 2Ω is connected to a silver voltameter. If the current of 1.5A flows through the circuit, the resistance of the voltameter is

4Ω

2Ω

6Ω

1Ω

5Ω

Given, E=−6V,r=2Ω and i=1.5A We know that, current across a circuit, i=r+RE​ ⇒1.5=2+R6​ ⇒2+R=1.56​ or, R=4−2=2Ω