A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current ( l in the circuit versus the number of cells will be as shown in figure

Question

A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current ( l in the circuit versus the number of cells will be as shown in figure (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For a two cell battery I=(2E/2r)=(E/r) Similarly, for a n cell battery I=(nE/2r)=(E/r) So, current in the circuit does not depend on number of cells in the battery. Hence, the correct graph will be (c).

Q. A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current ( $l$ in the circuit versus the number of cells will be as shown in figure

For a two cell battery $I = \frac{2 E}{2 r} = \frac{E}{r}$ Similarly, for a n cell battery $I = \frac{n E}{2 r} = \frac{E}{r}$ So, current in the circuit does not depend on number of cells in the battery. Hence, the correct graph will be (c).

Q. A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current ( l in the circuit versus the number of cells will be as shown in figure

For a two cell battery I=2r2E​=rE​ Similarly, for a n cell battery I=2rnE​=rE​ So, current in the circuit does not depend on number of cells in the battery. Hence, the correct graph will be (c).

Q. A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current ( $l$ in the circuit versus the number of cells will be as shown in figure

For a two cell battery $I = \frac{2 E}{2 r} = \frac{E}{r}$ Similarly, for a n cell battery $I = \frac{n E}{2 r} = \frac{E}{r}$ So, current in the circuit does not depend on number of cells in the battery. Hence, the correct graph will be (c).