A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12 ms-1. If the mass of the ball is 0.15 kg, the imparted to the ball is

Question

A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12 ms-1. If the mass of the ball is 0.15 kg, the imparted to the ball is (A) 36 N-s (B) 3.6 N-s (C) 0.36 N-s (D) 0.036 N-s

Tardigrade Admin · Accepted Answer

The initial momentum of ball P 1= m v , after batsman hits ball and reverses its direction, momentum of ball P 2=- m v Magnitude of change in momentum Δ p =| P 2- P 1|=|-2 m v |=2 m | v | from data given in question m =0.15 kg ;| v |=12 m / s Δ P =2 × 0.15 × 12=3.6 kgm / s

Q. A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of $12 m s^{- 1}$ . If the mass of the ball is 0.15 kg, the imparted to the ball is

$36 N - s$

$3.6 N - s$

$0.36 N - s$

$0.036 N - s$

Q. A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12ms−1. If the mass of the ball is 0.15 kg, the imparted to the ball is

36N−s

3.6N−s

0.36N−s

0.036N−s

The initial momentum of ball P1​=mv, after batsman hits ball and reverses its direction, momentum of ball P2​=−mv Magnitude of change in momentum Δp=∣P2​−P1​∣=∣−2mv∣=2m∣v∣ from data given in question m=0.15kg;∣v∣=12m/s ΔP=2×0.15×12=3.6kgm/s

Q. A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of $12 m s^{- 1}$ . If the mass of the ball is 0.15 kg, the imparted to the ball is

$36 N - s$

$3.6 N - s$

$0.36 N - s$

$0.036 N - s$