Q.
A bat moving at 10ms−1 towards a wall sends a sound signal of 8000Hz towards it. On reflection it hears a sound of frequency f. The value of f in Hz is close to (speed of sound = 320ms−1)
Observer O at the wall receives a frequency, f1=fv−vpv
Here v= speed of sound =320m/s
On reflection from the wall, source S received f2=f1vv+vs ⇒f2=fv−vsv+vs=8000(320−10320+10)=8000×3199339 ⇒f2=8516.12≈8516Hz