A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3 s . If the field strength is increased to 4 times of the earlier field strength, the time period will be (in seconds)

Question

A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3 s . If the field strength is increased to 4 times of the earlier field strength, the time period will be (in seconds) (A) 12 (B) 6 (C) 1.5 (D) 0.75

Tardigrade Admin · Accepted Answer

T=2 π √(1/M B) or T propto (1/√B) or (T2/T1)=√(B1/B2) or (T2/T3)=√(1/4) or T2=1.5 s

Q. A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of $3 s$ . If the field strength is increased to $4$ times of the earlier field strength, the time period will be (in seconds)

12

6

1.5

0.75

$T = 2 π \frac{1}{MB}$
or $T \propto \frac{1}{B}$ or $\frac{T _{2}}{T _{1}} = \frac{B _{1}}{B _{2}}$
or $\frac{T _{2}}{T _{3}} = \frac{1}{4}$ or $T_{2} = 1.5 s$

Q. A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3s . If the field strength is increased to 4 times of the earlier field strength, the time period will be (in seconds)

12

6

1.5

0.75

T=2πMB1​​ or T∝B​1​ or T1​T2​​=B2​B1​​​ or T3​T2​​=41​​ or T2​=1.5s

Q. A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of $3 s$ . If the field strength is increased to $4$ times of the earlier field strength, the time period will be (in seconds)

$T = 2 π \frac{1}{MB}$
or $T \propto \frac{1}{B}$ or $\frac{T _{2}}{T _{1}} = \frac{B _{1}}{B _{2}}$
or $\frac{T _{2}}{T _{3}} = \frac{1}{4}$ or $T_{2} = 1.5 s$