A bar magnet of magnetic moment 3.0 A m 2 is placed in a uniform magnetic induction field of 2 × 10-5 T. If each pole of the magnet experiences a force of 6 × 10-4 N, the length of the magnet is

Question

A bar magnet of magnetic moment 3.0 A m 2 is placed in a uniform magnetic induction field of 2 × 10-5 T. If each pole of the magnet experiences a force of 6 × 10-4 N, the length of the magnet is (A) 0.5 m (B) 0.3 m (C) 0.2 m (D) 0.1 m

Tardigrade Admin · Accepted Answer

F=m B ⇒ F=(M/L) × B ⇒ 6 × 10-4=(3/L) × 2 × 10-5 ⇒ L=0.1 m

Q. A bar magnet of magnetic moment $3.0 A m^{2}$ is placed in a uniform magnetic induction field of $2 \times 1 0^{- 5} T$ . If each pole of the magnet experiences a force of $6 \times 1 0^{- 4} N$ , the length of the magnet is

0.5 m

0.3 m

0.2 m

0.1 m

$F = m B \Rightarrow F = \frac{M}{L} \times B$
$\Rightarrow 6 \times 1 0^{- 4} = \frac{3}{L} \times 2 \times 1 0^{- 5}$
$\Rightarrow L = 0.1 m$

Q. A bar magnet of magnetic moment 3.0Am2 is placed in a uniform magnetic induction field of 2×10−5T. If each pole of the magnet experiences a force of 6×10−4N, the length of the magnet is