A bar magnet of length ' ℓ ' and magnetic dipole moment 'M' is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be :-

Question

A bar magnet of length ' ℓ ' and magnetic dipole moment 'M' is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be :- (A) (√2 M /π) (B) M (C) (3/π) M (D) 2 √2 ( M /π)

Tardigrade Admin · Accepted Answer

(2 π r /4)= L ⇒ r =(2 L /π) d =√2 r =(2 √2 L / π ) M text new =( M .d ) = mL (2 √2/π) =(2 √2 M /π)

Q. A bar magnet of length ' $ℓ$ ' and magnetic dipole moment ' $M$ ' is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be :-

$\frac{2 M}{π}$

$M$

$\frac{3}{π} M$

$22 \frac{M}{π}$

$\frac{2 π r}{4} = L$
$\Rightarrow r = \frac{2 L}{π}$
$d = 2 r = \frac{2 2 L}{π}$
$M_{new} = (M . d)$
$= m L {\frac{2 2}{π}} = \frac{2 2 M}{π}$

Q. A bar magnet of length ' ℓ ' and magnetic dipole moment 'M' is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be :-

π2​M​

M

π3​M

22​πM​

42πr​=L ⇒r=π2L​ d=2​r=π22L​​ Mnew ​=(M.d) =mL{π22​​}=π22​M​

Q. A bar magnet of length ' $ℓ$ ' and magnetic dipole moment ' $M$ ' is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be :-

$\frac{2 M}{π}$

$M$

$\frac{3}{π} M$

$22 \frac{M}{π}$

$\frac{2 π r}{4} = L$
$\Rightarrow r = \frac{2 L}{π}$
$d = 2 r = \frac{2 2 L}{π}$
$M_{new} = (M . d)$
$= m L {\frac{2 2}{π}} = \frac{2 2 M}{π}$