A balloon is rising vertically up with a velocity of 29 ms -1 . A stone is dropped from it and it reaches the ground in 10 s. The height of the balloon when the stone was dropped from it is (g=9.8 ms -1)

Question

A balloon is rising vertically up with a velocity of 29 ms -1 . A stone is dropped from it and it reaches the ground in 10 s. The height of the balloon when the stone was dropped from it is (g=9.8 ms -1) (A) 400 m (B) 150 m (C) 100 m (D) 200 m

Tardigrade Admin · Accepted Answer

For a stone which is thrown downwards from a balloon rising upwards, the equation of motion is h =-u t+(1/2) g t2 =-29 × 10+(1/2) × 9.8 ×(10)2 =-290+490 =200 m

Q. A balloon is rising vertically up with a velocity of $29 m s^{- 1} .$ A stone is dropped from it and it reaches the ground in $10 s$ . The height of the balloon when the stone was dropped from it is $(g = 9.8 m s^{- 1})$

400 m

150 m

100 m

200 m

For a stone which is thrown downwards from a balloon rising upwards, the equation of motion is
$h = - u t + \frac{1}{2} g t^{2}$
$= - 29 \times 10 + \frac{1}{2} \times 9.8 \times (10)^{2}$
$= - 290 + 490$
$= 200 m$

Q. A balloon is rising vertically up with a velocity of 29ms−1. A stone is dropped from it and it reaches the ground in 10s. The height of the balloon when the stone was dropped from it is (g=9.8ms−1)