A balloon contains 500 text m3 of helium at 27° C and 1 atmosphere pressure. The volume of the helium at -3° C temperature and 0.5 atmosphere pressure will be:

Question

A balloon contains 500 text m3 of helium at 27° C and 1 atmosphere pressure. The volume of the helium at -3° C temperature and 0.5 atmosphere pressure will be: (A)  1000 text m3  (B)  900 text m3  (C)  700 text m3  (D)  500 text m3

Tardigrade Admin · Accepted Answer

Using gas equation law (P1V1/T1)=(P2V2/T2) or (1× 500/300)=(0.5× V2/270) V2=900 m3

Q. A balloon contains $500 m^{3}$ of helium at $27^{\circ} C$ and 1 atmosphere pressure. The volume of the helium at $- 3^{\circ} C$ temperature and 0.5 atmosphere pressure will be:

$1000 m^{3}$

$900 m^{3}$

$700 m^{3}$

$500 m^{3}$

Using gas equation law $\frac{P _{1} V _{1}}{T _{1}} = \frac{P _{2} V _{2}}{T _{2}}$ or $\frac{1 \times 500}{300} = \frac{0.5 \times V _{2}}{270}$ $V_{2} = 900 m^{3}$

Q. A balloon contains 500m3 of helium at 27∘C and 1 atmosphere pressure. The volume of the helium at −3∘C temperature and 0.5 atmosphere pressure will be:

1000m3

900m3

700m3

500m3