Q.
A ball of mass 0.5kg is moving with a velocity v of 2m/s. It is subjected to a force of x newton in 2s. Because of this force, the ball moves with velocity of 3m/s. The value of x is
3147
218
ManipalManipal 2010Laws of Motion
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Solution:
If a constant force F is applied on a body for a short interval of time Δt, then the impulse of this force is FΔt.
When mass of body is m, an applying force F, for a time interval Δt, the body suffers a velocity change Δv, then F=ma=mΔtΔv ⇒FΔt=mΔv
Given, F=x newton, Δt=2s,v1=2m/s v2=3m/s,m=0.5kg ∴x×2=0.5×1 ⇒x=20.5=0.25N