A ball is projected from ground at an angle 45° with horizontal from distance d1 from the foot of a pole and just after touching the top of pole it the falls on ground at distance d2 from pole on other side, the height of pole is

Question

A ball is projected from ground at an angle 45° with horizontal from distance d1 from the foot of a pole and just after touching the top of pole it the falls on ground at distance d2 from pole on other side, the height of pole is (A) 2 √d1 d2 (B) (d1+d2/4) (C) (2 d1 d2/d1+d2) (D) (d1 d2/d1+d2)

Tardigrade Admin · Accepted Answer

Repeated. tan θ+ tan β= tan θ (y/d1)+(y/d2)= tan 45° y=((d1 d2/d1+d2))

Q. A ball is projected from ground at an angle $4 5^{\circ}$ with horizontal from distance $d_{1}$ from the foot of a pole and just after touching the top of pole it the falls on ground at distance $d_{2}$ from pole on other side, the height of pole is

$2 d_{1} d_{2}$

$\frac{d _{1} + d _{2}}{4}$

$\frac{2 d _{1} d _{2}}{d _{1} + d _{2}}$

$\frac{d _{1} d _{2}}{d _{1} + d _{2}}$

Repeated.
$tan θ + tan β = tan θ$
$\frac{y}{d _{1}} + \frac{y}{d _{2}} = tan 4 5^{\circ}$
$y = (\frac{d _{1} d _{2}}{d _{1} + d _{2}})$

Q. A ball is projected from ground at an angle 45∘ with horizontal from distance d1​ from the foot of a pole and just after touching the top of pole it the falls on ground at distance d2​ from pole on other side, the height of pole is

2d1​d2​​

4d1​+d2​​

d1​+d2​2d1​d2​​

d1​+d2​d1​d2​​