A ball is falling freely from a height. When it reaches 10 m height from the ground its velocity is v0. It collides with the ground and loses 50 % of its energy and rises back to height of 10 m. Then the velocity v0 is

Question

A ball is falling freely from a height. When it reaches 10 m height from the ground its velocity is v0. It collides with the ground and loses 50 % of its energy and rises back to height of 10 m. Then the velocity v0 is (A) 7 m / s (B) 10 m / s (C) 14 m / s (D) 16 m / s

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0f082537a25935c613b85ab610bc7840-.png" /> At height 10 m, the kinetic energy equal to potential energy then (1/2) mv02=mgh (1/2) v02 =9.8 × 10 v02 =2 × 9.8 × 10 v0 =√196 v0 =14 m / s

Q. A ball is falling freely from a height. When it reaches $10 m$ height from the ground its velocity is $v_{0}$ . It collides with the ground and loses $50%$ of its energy and rises back to height of $10 m$ . Then the velocity $v_{0}$ is

7 m / s

10 m / s

14 m / s

16 m / s

At height $10 m$ , the kinetic energy equal to potential energy then
$\frac{1}{2} m v_{0}^{2} = m g h$
$\frac{1}{2} v_{0}^{2} = 9.8 \times 10$
$v_{0}^{2} = 2 \times 9.8 \times 10$
$v_{0} = 196$
$v_{0} = 14 m / s$

Q. A ball is falling freely from a height. When it reaches 10m height from the ground its velocity is v0​. It collides with the ground and loses 50% of its energy and rises back to height of 10m. Then the velocity v0​ is