A ball falling in a lake depth 200 m shows a decrease of 0.1 % in its volume at the bottom then the bulk modulus of the material of the ball is:

Question

A ball falling in a lake depth 200 m shows a decrease of 0.1 % in its volume at the bottom then the bulk modulus of the material of the ball is: (A) 19.6 × 108 N / m 2 (B) 19.2 × 107 N / m 2 (C) 24 × 109 N / m 2 (D) 24 × 105 N / m 2

Tardigrade Admin · Accepted Answer

K =(Δ p/ text Volume strain ) =(h d g/ text Volume strain ) =(200 × 103 × 9.8/0.1 × 10-2) =19.6 × 108 N / m 2

Q. A ball falling in a lake depth $200 m$ shows a decrease of $0.1%$ in its volume at the bottom then the bulk modulus of the material of the ball is:

$19.6 \times 1 0^{8} N / m^{2}$

$19.2 \times 1 0^{7} N / m^{2}$

$24 \times 1 0^{9} N / m^{2}$

$24 \times 1 0^{5} N / m^{2}$

$K = \frac{Δ p}{Volume strain}$
$= \frac{h d g}{Volume strain}$
$= \frac{200 \times 1 0 ^{3} \times 9.8}{0.1 \times 1 0 ^{- 2}}$
$= 19.6 \times 1 0^{8} N / m^{2}$

Q. A ball falling in a lake depth 200m shows a decrease of 0.1% in its volume at the bottom then the bulk modulus of the material of the ball is:

19.6×108N/m2

19.2×107N/m2

24×109N/m2

24×105N/m2