A B C D is a square, A=(1,2), B=(3,-4). If line C D passes through (3,8), then midpoint of C D is:

Question

A B C D is a square, A=(1,2), B=(3,-4). If line C D passes through (3,8), then midpoint of C D is: (A) ((28/5), (1/5)) (B) (-4,-3) (C) ((24/25), (1/5)) (D) (8,1)

Tardigrade Admin · Accepted Answer

Correct answer is (a) ((28/5), (1/5))

Q. $A BC D$ is a square, $A = (1, 2), B = (3, - 4)$ . If line $C D$ passes through $(3, 8)$ , then midpoint of $C D$ is:

$(\frac{28}{5}, \frac{1}{5})$

$(- 4, - 3)$

$(\frac{24}{25}, \frac{1}{5})$

$(8, 1)$

Correct answer is (a) $(\frac{28}{5}, \frac{1}{5})$

Q. ABCD is a square, A=(1,2),B=(3,−4). If line CD passes through (3,8), then midpoint of CD is:

(528​,51​)

(−4,−3)

(2524​,51​)

(8,1)

Correct answer is (a) (528​,51​)

Q. $A BC D$ is a square, $A = (1, 2), B = (3, - 4)$ . If line $C D$ passes through $(3, 8)$ , then midpoint of $C D$ is:

$(\frac{28}{5}, \frac{1}{5})$

$(- 4, - 3)$

$(\frac{24}{25}, \frac{1}{5})$

$(8, 1)$

Correct answer is (a) $(\frac{28}{5}, \frac{1}{5})$