A 5.8% (wt./vol.) NaCl solution will exert an osmotic pressure closest to which one of the following:

Question

A 5.8% (wt./vol.) NaCl solution will exert an osmotic pressure closest to which one of the following: (A) 5.8% (wt./vol.) sucrose solution (B) 5.8% (wt./vol.) glucose solution (C) 2 molal sucrose solution (D) 1 molal glucose solution

Tardigrade Admin · Accepted Answer

5.8 % (wt./vol.) NaCl has molarity =(5.8 × 1000/58.5 × 100)=1 M Thus it will show approximately 2 M in solution (∵ i=2., strong electrolyte)

Q. A 5.8% (wt./vol.) NaCl solution will exert an osmotic pressure closest to which one of the following:

5.8% (wt./vol.) sucrose solution

5.8% (wt./vol.) glucose solution

2 molal sucrose solution

1 molal glucose solution

$5.8%$ (wt./vol.) NaCl has molarity
$= \frac{5.8 \times 1000}{58.5 \times 100} = 1 M$
Thus it will show approximately 2 M in solution $(∵$ i=2., strong electrolyte)

Q. A 5.8% (wt./vol.) NaCl solution will exert an osmotic pressure closest to which one of the following:

5.8% (wt./vol.) sucrose solution

5.8% (wt./vol.) glucose solution

2 molal sucrose solution

1 molal glucose solution

5.8% (wt./vol.) NaCl has molarity =58.5×1005.8×1000​=1M Thus it will show approximately 2 M in solution (∵ i=2., strong electrolyte)

$5.8%$ (wt./vol.) NaCl has molarity
$= \frac{5.8 \times 1000}{58.5 \times 100} = 1 M$
Thus it will show approximately 2 M in solution $(∵$ i=2., strong electrolyte)