Question

A 16 kg block moving on a frictionless horizontal surface with a velocity of 4 m/s compresses an ideal spring and comes to rest. If the force constant of the spring be 100 N/m, then the spring is compressed by

• A. 1.6 m
• B. 4 m
• C. 6.1 m
• D. 3.2 m

Answer 1

Answer: (A)

Kinetic energy of the block is
$K=\frac{1}{2}m{v}^2$
This kinetic energy is equal to the work done by the block before coming to rest. The work done in compressing the spring through a distance x from its normal length is
$W=\frac{1}{2}k{x}^2$
$\therefore$ $\frac{1}{2}m{v}^2=\frac{1}{2}k{x}^2\Rightarrow x=v\sqrt{\frac{m}{k}}$
Given, v = 4 m/s, m = 16 kg, k = 100 N/m
= $x=4\times \sqrt{\frac{16}{100}}=1.6m$