A 1 m long wire is lying at right angles to the magnetic field. A force of 1 kg wt. is acting on it in a magnetic field of 0.98 T . The current flowing in it will be

Question

A 1 m long wire is lying at right angles to the magnetic field. A force of 1 kg wt. is acting on it in a magnetic field of 0.98 T . The current flowing in it will be (A) 100 A (B) 10 A (C) 1 A (D) zero

Tardigrade Admin · Accepted Answer

Force on a current carrying wire of length

I

, carrying current

I

, kept in a magnetic field

B

is given by

F = I 1 \times B = I Bl sin θ

where

θ

is the angle the wire makes with the magnetic field.
Given,

1 = 1 m, θ = 9 0^{\circ}, F = 1 k g - wt = 9.8 N

,

B = 0.98 T

I = \frac{F}{lB} = \frac{9.8}{0.98 \times 1} = 10 A

Q. A 1m long wire is lying at right angles to the magnetic field. A force of 1kgwt. is acting on it in a magnetic field of 0.98T . The current flowing in it will be

100 A

10 A

1 A

zero

Force on a current carrying wire of length I, carrying current I, kept in a magnetic field B is given by F=I1×B=IBlsinθ where θ is the angle the wire makes with the magnetic field. Given, 1=1m,θ=90∘,F=1kg−wt=9.8N, B=0.98T I=lBF​=0.98×19.8​=10A

Q. A $1 m$ long wire is lying at right angles to the magnetic field. $A$ force of $1 k g wt$ . is acting on it in a magnetic field of $0.98 T$ . The current flowing in it will be