A 1 L solution of pH =1, is diluted up to 10 times. What volume of a solution with pH =2 is to be added in diluted solution so that pH does not change?

Question

A 1 L solution of pH =1, is diluted up to 10 times. What volume of a solution with pH =2 is to be added in diluted solution so that pH does not change? (A) 10 L (B) 100 L (C) 1 L (D) 25 L

Tardigrade Admin · Accepted Answer

After dilution [ H +]=10-2 pH =2 Let V L solution of pH =2 is added in original solution so that pH remains fixed ∴[ H +]=(10-2 x+V × 10-2/10+V)=10-2 This result is independent of volume taken

Q. A $1 L$ solution of $p H = 1$ , is diluted up to $10$ times. What volume of a solution with $p H = 2$ is to be added in diluted solution so that $p H$ does not change?

$10 L$

$100 L$

$1 L$

$25 L$

After dilution $[H^{+}] = 1 0^{- 2}$
$p H = 2$
Let $V$ L solution of $p H = 2$ is added in original solution so that $p H$ remains fixed
$∴ [H^{+}] = \frac{1 0 ^{- 2} x + V \times 1 0 ^{- 2}}{10 + V} = 1 0^{- 2}$
This result is independent of volume taken

Q. A 1L solution of pH=1, is diluted up to 10 times. What volume of a solution with pH=2 is to be added in diluted solution so that pH does not change?

10L

100L

1L

25L