Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A 0.2 kΩ resistor and 15 μ F capacitor are connected in series to a 220 V, 50 Hz ac source. The impedance of the circuit is
Q. A
0.2
k
Ω
resistor and
15
μ
F
capacitor are connected in series to a
220
V
,
50
Hz
ac source. The impedance of the circuit is
2650
192
Alternating Current
Report Error
A
250
Ω
6%
B
268
Ω
9%
C
29.15
Ω
14%
D
291.5
Ω
72%
Solution:
Here,
R
=
0.2
k
Ω
=
200
Ω
C
=
15
μ
F
=
15
×
1
0
−
6
F
,
V
r
m
s
=
220
V
,
υ
=
50
Hz
Capacitive reactance,
X
C
=
2
π
υ
C
1
=
2
×
3.14
×
50
×
15
×
1
0
−
6
1
=
212
Ω
The impedance of the
RC
circuit is
Z
=
R
2
+
X
C
2
=
(
200
)
2
+
(
212
)
2
=
291.5
Ω