Tardigrade
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Tardigrade
Question
Chemistry
9.8 g of H2SO4 is present in 2 L of a solution. The molarity of the solution is
Q. 9.8 g of
H
2
S
O
4
is present in 2 L of a solution. The molarity of the solution is
2327
220
CMC Medical
CMC Medical 2010
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A
0.1 M
B
0.05 M
C
0.2 M
D
0.01 M
Solution:
Amount of
H
2
S
O
4
=
9.8
g
Volume of solution = 2 L Moles of
H
2
S
O
4
=
molar
mass
mass
of
H
2
S
O
4
=
98
g
m
o
l
−
1
9.8
g
(
∵
Molar mass of
H
2
S
O
4
= 98) Molarity
=
volume
of
solution
moles
of
H
2
S
O
4
=
2
L
0.1
m
o
l
=
0.05
m
o
l
L
−
1
or
0.05
M