8 gm O 2, 14 gm N 2 and 22 gm CO 2 is mixed in a container of 10 litre capacity at 27° C. The pressure exerted by the mixture in terms of atmospheric pressure will be -

Question

8 gm O 2, 14 gm N 2 and 22 gm CO 2 is mixed in a container of 10 litre capacity at 27° C. The pressure exerted by the mixture in terms of atmospheric pressure will be - (A) 1 (B) 3 (C) 9 (D) 18

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/97bd24e48f61aadd3409221f8a4184fe-.png" /> P V=n R T P=(n R T/V)=(5/4) × (8.31 × 300/10 × 10-3) =3 atm

Q. $8 g m O_{2}, 14 g m N_{2}$ and $22 g m C O_{2}$ is mixed in a container of $10$ litre capacity at $2 7^{\circ} C$ . The pressure exerted by the mixture in terms of atmospheric pressure will be -

1

3

9

18

$P V = n RT$
$P = \frac{n RT}{V} = \frac{5}{4} \times \frac{8.31 \times 300}{10 \times 1 0 ^{- 3}}$
$= 3$ atm

Q. 8gmO2​,14gmN2​ and 22gmCO2​ is mixed in a container of 10 litre capacity at 27∘C. The pressure exerted by the mixture in terms of atmospheric pressure will be -

1

3

9

18

PV=nRT P=VnRT​=45​×10×10−38.31×300​ =3 atm

Q. $8 g m O_{2}, 14 g m N_{2}$ and $22 g m C O_{2}$ is mixed in a container of $10$ litre capacity at $2 7^{\circ} C$ . The pressure exerted by the mixture in terms of atmospheric pressure will be -

$P V = n RT$
$P = \frac{n RT}{V} = \frac{5}{4} \times \frac{8.31 \times 300}{10 \times 1 0 ^{- 3}}$
$= 3$ atm