Question

540 g of ice of $0{}^{\circ }C$ is mixed with 540 g of water at $80{}^{\circ }C$ . The final temperature of the mixture is

• A. $0{}^{\circ }C$
• B. $40{}^{\circ }C$
• C. $80{}^{\circ }C$
• D. less than $0{}^{\circ }C$

Answer 1

Answer: (A)

Heat taken by ice to melt at $0^{o}C$ is $Q_1=mL=540\times 80=43200cal$ Heat given by water to cool upto $0^{o}C$ is $Q_2=m\times s\times \Delta \theta$ $=540\times 1\times (80-0)$ $=43200cal$ Heat given by water = Heat absorbed by ice $\therefore$ Three will be no change in the temperature of mixture. Hence, the temperature of mixture will be $0^{o}C$ .