50 mL of hydrogen diffuses out through a small hole of a vessel, in 20 minutes. The time taken by 40 mL of oxygen to diffuse out is

Question

50 mL of hydrogen diffuses out through a small hole of a vessel, in 20 minutes. The time taken by 40 mL of oxygen to diffuse out is (A) 32 minutes (B) 64 minutes (C) 8 minutes (D) 12 minutes

Tardigrade Admin · Accepted Answer

Rate ( H 2)=(50/20)=2.5 Rate ( O 2)=(40/t) ( r H 2/ r O )=(2.5/40 / t )=√( M O2 / M H 2)=√(32 / 2)=4 ⇒ 2.5 t =160 t =64 min

Q. 50 mL of hydrogen diffuses out through a small hole of a vessel, in 20 minutes. The time taken by 40 mL of oxygen to diffuse out is

32 minutes

64 minutes

8 minutes

12 minutes

Rate $(H_{2}) = \frac{50}{20} = 2.5$
Rate $(O_{2}) = \frac{40}{t}$
$\frac{r _{H_{2}}}{r _{O}} = \frac{2.5}{40/ t} = (M_{O_{2}} / M_{H_{2}}) = (32/2) = 4$
$\Rightarrow 2.5 t = 160$
$t = 64 min$

Q. 50 mL of hydrogen diffuses out through a small hole of a vessel, in 20 minutes. The time taken by 40 mL of oxygen to diffuse out is

32 minutes

64 minutes

8 minutes

12 minutes

Rate (H2​)=2050​=2.5 Rate (O2​)=t40​ rO​rH2​​​=40/t2.5​=(MO2​​/MH2​​)​=(32/2)​=4 ⇒2.5t=160 t=64min

Rate $(H_{2}) = \frac{50}{20} = 2.5$
Rate $(O_{2}) = \frac{40}{t}$
$\frac{r _{H_{2}}}{r _{O}} = \frac{2.5}{40/ t} = (M_{O_{2}} / M_{H_{2}}) = (32/2) = 4$
$\Rightarrow 2.5 t = 160$
$t = 64 min$