Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
4K2Cr2O7 ->[Heat] 4K2CrO4 + 3O2 + X. In the above reaction X is:
Q.
4
K
X
2
Cr
X
2
O
X
7
Heat
4
K
X
2
CrO
X
4
+
3
O
X
2
+
X
⋅
In the above reaction X is:
3551
248
Manipal
Manipal 2005
Report Error
A
CrO
X
3
32%
B
Cr
X
2
O
X
7
15%
C
Cr
X
2
O
X
3
48%
D
CrO
X
5
5%
Solution:
Potassium dichromate, on heating gives oxygen and chromic oxide
(
Cr
X
2
O
X
3
)
.
4
K
X
2
Cr
X
2
O
X
7
Δ
4
K
X
2
CrO
X
4
+
3
O
X
2
+
2
Cr
X
2
O
X
3