Question

$35.4mL$ of $HCl$ is required for the neutralization of a solution containing $0.275g$ of sodium hydroxide. The normality of hydrochloric acid is?

• A. 0.97 N
• B. 0.142 N
• C. 0.194 N
• D. 0.244 N

Answer 1

Answer: (C)

We know that $1g$ equivalent weight of
$NaOH=40_g$
$\therefore 40g$ of $NaOH=1g$ eq. of $NaOH$
$\therefore 0.275g$ of $NaOH=\frac{1}{40}\times 0.275eq$
$=\frac{1}{40}\times 0.275\times 1000$
$=6.88$ meq
$\therefore N_1{V}_1=N_2{V}_2$
$(HCl)(NaOH)$
$N_1\times 35.4=6.88$
$(\because meq=NV)$
$N_1=0.194$