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Question
Chemistry
(32Ge76, 34Se76) and (14Si30, 16S32) are examples of
Q.
(
32
G
e
76
,
34
S
e
76
)
and
(
14
S
i
30
,
16
S
32
)
are examples of
2494
212
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A
isotopes and isobars
B
isobars and isotones
C
isotones and isotopes
D
isobars and isotopes
Solution:
32
G
e
76
and
34
S
e
76
have the same mass number but different atomic number, so they are isobars.
Number of neutrons,
in
14
S
i
30
=
30
−
14
=
16
in
16
S
32
=
32
−
16
=
16
Because of the presence of same number of neutrons,
14
S
i
30
and
16
S
32
are called isotones.