Question

3 identical point particles of mass M move in such a way that distance between particles is 'd' which remain constant. Only force is the gravitational force between particles. Then magnitude of relative velocity (in $m/s$ ) of one particle with respect to other particle will be : [Take $\sqrt{\frac{GM}{d}}=\sqrt{3}m/s$ ]

Answer 1

Answer: 3

Particle will move in circle.

$2\frac{G{M}^2}{d^2}cos30^{\circ }=\frac{M{V}^2}{R}$
$v=\sqrt{\frac{GM}{d}}=\sqrt{3}m/s[R\sqrt{3}=d]$
Relative velocity $=2vcos30^{\circ }=3m/s$