Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
2MnO-4 + 5H2O2 + 6H+ → 2Z + 502 + 8H2O. In this reaction Z is
Q.
2
M
n
O
4
−
+
5
H
2
O
2
+
6
H
+
→
2
Z
+
5
0
2
+
8
H
2
O
. In this reaction
Z
is
2283
289
Redox Reactions
Report Error
A
M
n
+
2
34%
B
M
n
+
4
22%
C
M
n
O
2
19%
D
M
n
24%
Solution:
2
M
n
O
4
−
+
5
H
2
O
2
+
6
H
+
−
+
2
M
n
2
+
+
5
O
2
+
8
H
2
O